contestada

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

x = negative StartFraction 2 plus or minus StartRoot 19 EndRoot Over 3 EndFraction
x = negative StartFraction 2 plus or minus 2 StartRoot 19 EndRoot Over 3 EndFraction
x = StartFraction 2 plus or minus StartRoot 19 EndRoot Over 3 EndFraction
x = StartFraction 2 plus or minus 2 StartRoot 19 EndRoot Over 3 EndFraction

Respuesta :

arielfairy

Answer: x = -2+/- ✔️19

———————

3

(A on Edge.)

pstnonsonjoku

The solution for the quadratic is obtained as -2/3 ± 1/3√19.

What is a quadratic equation?

A quadratic equation is any equation of the sort; ax^2 + bx +c = 0. It is a polynomial of degree two.

Now we have the equation; –3x2 – 4x + 5, the quadratic formula is  given by; -b±√b^2 - 4ac/2a. When we subtitute the given equation, we obtain;

x = -(-4)±√(-4)^2 - 4(-3)(5)/2(-3). This gives us the result; -2/3 ± 1/3√19.

Learn more about quadratic equation: https://brainly.com/question/2263981

Otras preguntas