Answer:
0.2828.
Step-by-step explanation:
From the information given:
Therefore: P(No Cancer)=1-P(Cancer)=1-0.006=0.994
We want to determine the probability that a person with a positive test result has cancer. i,e. P(Cancer|Positive)
Using Bayes Theorem for Conditional Probability
[tex]P(Cancer|Positive)=\dfrac{P(Positive|Cancer)P(Cancer)}{P(Positive|Cancer)P(Cancer)+P(Positive|No Cancer)P(No Cancer)}\\=\dfrac{0.98X0.006}{0.98X0.006+0.015X0.994}[/tex][tex]P(Cancer|Positive)=0.2828[/tex]
Therefore, the probability that a person with a positive test result has cancer is 0.2828.