A droplet of ink in an industrial ink-jet printer carries a charge of 1.6 x 10^-10 C and is deflected onto paper by a force of 3.2 x 10-4 N. Show that the strength of the electric field to produce this force is 2 million N/C.

Respuesta :

Answer:

Electric field is 2 million N/C.

Explanation:

Given that,

Charge on an industrial ink-jet printer, [tex]q=1.6\times 10^{-10}\ C[/tex]

Electric force acting on it, [tex]F=3.2\times 10^{-4}\ N[/tex]

Due to electric field, an electric field is produced in its surrounding. The electric force is given by :

[tex]F=qE\\\\E=\dfrac{F}{q}\\\\E=\dfrac{3.2\times 10^{-4}}{1.6\times 10^{-10}}\\\\E=2000000\ N/C\\\\E=2\times 10^6\ N/C\\\\E=2\ \text{million}\ N/C[/tex]

Hence, proved.

The Strength of the electric field produced is[tex]2 \times 10^7 N/C[/tex]

  • The calculation is as follows:

Electric Field represent the region where an electric force should be experienced.

It is represented mathematically as,

[tex]E = F\div Q[/tex]

Here

E = Electric field strength,

F = electric force,

Q = test charge.

So,

[tex]E= 3.2 \times 10^{-4}\div 1.6 \times 10^{-11}\\\\E= 2 \times 10^{7} N/C[/tex]

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