Given:
The dimensions of the square photo are 12'' × 12''.
The frame is 2 inches wider than the photo in both length and width.
To find:
The perimeter of the frame.
Solution:
We have,
Length of the photo = 12 inches
Width of the photo = 12 inches
The frame is 2 inches wider than the photo in both length and width. So,
Length of the frame = 12+2 inches
= 14 inches
Width of the frame = 12 inches
= 14 inches
The perimeter of a square is:
[tex]P=4a[/tex]
Where, a is the side length.
Now, the perimeter of the square frame with side 14 inches is:
[tex]P=4(14)[/tex]
[tex]P=56[/tex]
Therefore, the perimeter of the square frame is 56 inches, Hence, option A is correct.
