Answer:
(a) When elevator descends weight will be 155.026 lb
(b) When elevator ascends weight will be 164.954 lb
Explanation:
It is given weight of man on the floor of elevator F = 160 lb
Acceleration due to gravity [tex]g=32.17ft/sec^2[/tex]
At the floor of elevator weight is equal to [tex]W=mg[/tex]
So [tex]160=m\times 32.17[/tex]
m = [tex]4.973lbsec^2/ft[/tex]
(ii) When the elevator descends with uniform acceleration [tex]1ft/sec^2[/tex]
Weight will be equal to [tex]W=m(g+a)=4.973\times (32.17+1)=155.026lb[/tex]
(ii) When elevator is moving upward
Weight is equal to [tex]W=m(g+a)=4.973\times (32.17+1)=164.954lb[/tex]
