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A 9.5-kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of 75 cm between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 2.2 m/s. a) the magnitude of the centripital force acting on the monkey. b) the magnitude of the tension in the monkey's arm.

Respuesta :

Answer:

(a) The centripetal force equals 61.31 Newtons

(b) The tension in the monkey's arm is equal to 154.51 Newtons

Explanation:

The equation for centripetal force is:

[tex]Fc=mV^2/r[/tex]

Here, m = 9.5 kg

V = 2.2 m/s

and r = 0.75 m

(a) Calculating the centripetal force using this equation we get:

[tex]F_c= 61.31 N[/tex]

(b) To calculate the tension in the monkey's arm we need to remember that the arm has to take the weight of the monkey AND resist the centrifugal force by the monkey's circular movement.

Weight of monkey = 9.5 * 9.81 = 93.2 N

Tension in monkey's arm = Weight + centrifugal force

Tension in monkey's arm = 93.2 + 61.31

Tension in monkey's arm = 154.51 N

Olajidey

Answer:

a)= 61.3N

b) = 154.4N

Explanation:

Given that ,

mass of monkey = 9.5kg

radial distance r = 75cm = 0.75m

speed v = 2.2m/s

The centripetal force is given by:

[tex]F_c=\frac{m*v^2}{r}\\F_c=\frac{9.5kg*(2.2m/s)^2}{75*10^{-2}m}\\F_c=61.3N[/tex]

The tension will be equal to the centripetal force acting on the arm of the monkey plus its weight:

[tex]T=m*g+\frac{m*v^2}{r}\\\\T=9.5kg*9.8m/s^2+61.3N\\T=154.4N[/tex]

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