To help support a flagpole, a 50-foot-long tether is tied to the pole at a point 40 feet above the
ground. The tether is pulled taut and tied to an anchor in the ground. How far away from the base
of the pole is the anchor?

The height at which the tether is tied above the ground , and the distance from the base of the pole to the anchor, forms the legs of the right triangle.

Let the distance from the base to the anchor be x.

Then from Pythagoras Theorem,

[tex] {x}^{2} + {40}^{2} = {50}^{2} [/tex]

[tex]{x}^{2}= {50}^{2} - {40}^{2} [/tex]

[tex] {x}^{2} = 2500 - 1600[/tex]

[tex]{x}^{2}= 900[/tex]

Take square root:

[tex]{x}= \sqrt{900} [/tex]

[tex]x = 30ft[/tex]

To help support a flagpole, a 50-foot-long tether is tied to the pole at a point 40 feet above the ground. The tether is pulled taut and tied to an anchor in the ground. How far away from the base of the pole is the anchor?

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To help support a flagpole, a 50-foot-long tether is tied to the pole at a point 40 feet above the
ground. The tether is pulled taut and tied to an anchor in the ground. How far away from the base
of the pole is the anchor?