Answer:
The magnitude of the magnetic field is 0.83 T
Explanation:
Given :
Speed of electron inside television tube (v) = [tex]2.8[/tex]×[tex]10^7 m/s[/tex]
Radius of electron moving path ([tex]r[/tex]) = [tex]0.190[/tex]×[tex]10^-3m[/tex]
According lorentz force in magnetic field is,
∴ [tex]F = q (v[/tex] ×[tex]B)[/tex]
Where, [tex]q[/tex] = charge of electron, [tex]v[/tex] = speed of electron, [tex]B[/tex] = magnetic field and
[tex]F[/tex] = force on electron.
when electron is moving in circular orbit the force is given by,
∴ [tex]F = mv^2/r[/tex]
so we equate above both equation.
∴ [tex]mv^2/r = q(v[/tex] × [tex]B)[/tex]
∴ [tex]B = mv/qr[/tex]
∴ [tex]B = 9.1[/tex]×[tex]10^-31[/tex]×[tex]2.8[/tex]×[tex]10^7[/tex][tex]/1.6[/tex]×[tex]10^-19[/tex]×[tex]0.190[/tex]×[tex]10^-3[/tex]
∴ [tex]B =[/tex] 0.83 Tesla
Therefore, the magnitude of the magnetic field is 0.83 T.
