Answer:
Step-by-step explanation:
Let X represent the birthweight of infant.
X is N(3600, 600)
To get within 200 gms from the mean
we must have x lying in (3400, 3800)
Let sample size be n
For this sample, sample mean is N(3600, 600/sqrt n)
For 90% confidence about the mean weight fromstd normal distribution we find that
z = ±1.645
So margin of error = 1.645*std error =200
[tex]1.645*\frac{600}{\sqrt{n} } <200\\\sqrt{n} >3*1.645\\n >25[/tex]
Atleast 25 numbers should beconsidered.