Answer:
The output force on the larger area piston ( F ) = [tex]\frac{F_{1} }{A_{1} }[/tex] × A
Explanation:
Let
Area of the smaller cross section piston = [tex]A_{1}[/tex]
Force of the smaller cross section piston = [tex]F_{1}[/tex]
Area of the larger cross section piston = A
Force of the larger cross section piston = F
So the Pressure on the smaller cross section piston [tex]P_{1}[/tex] = [tex]\frac{F_{1} }{A_{1} }[/tex] ----------- (1)
And the Pressure on the larger cross section piston [tex]P_{}[/tex] = [tex]\frac{F}{A}[/tex] -------------(2)
When a given force is applied to the small piston the pressure on the smaller piston is equal to pressure on the larger piston. i.e. equation (1) is equal to equation (2)
⇒ [tex]P_{1}[/tex] = [tex]P_{}[/tex]
⇒ [tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F}{A}[/tex]
⇒ F = [tex]\frac{F_{1} }{A_{1} }[/tex] × A ------------(3)
This is the output force on the larger area piston.