A hydraulic device has two pistons, one with a small cross-section area and another piston with a larger cross-section area. If a given force is applied to the small piston, the output force on the larger-area piston will be

Respuesta :

Answer:

The output force on the larger area piston ( F ) = [tex]\frac{F_{1} }{A_{1} }[/tex] × A

Explanation:

Let

Area of the smaller cross section piston = [tex]A_{1}[/tex]

Force of the smaller cross section piston = [tex]F_{1}[/tex]

Area of the larger cross section piston = A

Force of the larger cross section piston = F

So the Pressure on the smaller cross section piston [tex]P_{1}[/tex] = [tex]\frac{F_{1} }{A_{1} }[/tex] ----------- (1)

And the Pressure on the larger cross section piston [tex]P_{}[/tex] = [tex]\frac{F}{A}[/tex] -------------(2)

When a given force is applied to the small piston the pressure on the smaller piston is equal to pressure on the larger piston. i.e. equation (1) is equal to equation (2)

⇒ [tex]P_{1}[/tex] = [tex]P_{}[/tex]

⇒ [tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F}{A}[/tex]

⇒ F = [tex]\frac{F_{1} }{A_{1} }[/tex] × A ------------(3)

This is the output force on the larger area piston.