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What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4= (x-6) and passes through the point (-2,-2)?

A) y=-2/3x-10/3
B) y=-2/3x+10/3
C) y=3/2x-1
B) y=3/2x+1

Respuesta :

hey475

Answer:

c is the closest to point (-2,-2)

Step-by-step explanation:

altavistard

Answer:

y = -x - 4

Step-by-step explanation:

Compare the given y-4= +1(x-6) to y - k = m(x - h), where (h, k) is a point on that line.  We then know immediately that the slope of the given line is -1/1, or m = -1.  

A line perpendicular to this given line that also passes through (-2, -2) is then:

y + 2 = -1(x + 2), or y + 2 = -x - 2, or y = -x - 4

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