Answer:
The value of R_low is 13.1 kΩ while that of R_high is 36.8 kΩ
Explanation:
The diagram is as given as
The circuit is an inverting op amp for which the gain is given as
[tex]A_v=\dfrac{R_2+R}{R_1+R_z}[/tex]
Here R2 is given as 450 kΩ.
R1 is given as 47 kΩ.
The gain is given as
[tex]A_v=-10\pm 0.5*\dfrac{10}{100}\\A_v=-10\pm 0.05[/tex]
For the Lowest value of R the value of the internal resistance rz is 0 and the gain is -10+0.05 so
[tex]A_v=-\dfrac{R_2+R}{R_1+R_z}\\-10+0.05=-\dfrac{450+R_l_o_w}{47+0}\\-9.95=-\dfrac{450+R_l_o_w}{47+0}\\R_l_o_w=13.1[/tex]
So the value of R_low is 13.1 kΩ
For the Highest value of R the value of the internal resistance rz is 1 kΩ and the gain is -10-0.05 so
[tex]A_v=-\dfrac{R_2+R}{R_1+R_z}\\-10-0.05=-\dfrac{450+R_{high}}{47+1}\\-10.05=-\dfrac{450+R_{high}}{47+1}\\R_{high}=36.8[/tex]
So the value of R_high is 36.8 kΩ