The area of the triangle with side 14, 12 and 6 unit is 35.78 unit²
The area of a triangle with sides a, b, c is given by:
[tex]A=\sqrt{s(s-a)(s-b)(s-c)} \\\\s=\frac{a+b+c}{2} \\\\Since:\\\\A=\sqrt{s(s-14)(s-12)(s-6)} \\\\s=\frac{14+12+6}{2}=16\\ \\A=\sqrt{16(16-14)(16-12)(16-6)} \\\\A=35.78\ unit[/tex]
The area of the triangle with side 14, 12 and 6 unit is 35.78 unit²
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