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Use the chemical equation to help calculate the mass in grams of zinc needed to produce 112 liters of hydrogen gas at standard temperature and pressure?

Respuesta :

Edufirst

Answer:

  • 327 g.

Explanation:

Assume the chemical equation:

  • Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

1. Convert 112 liters of hydrogen gas at STP to number of moles.

You can use the molar volume of a gas at STP equal to approximately 22.4 liters.

        [tex]112liter\times \dfrac{1mol}{22.4liter}=5mol[/tex]

2. Use the theoretical mole ratio

From the balanced chemical equation, 1 mol of Zn produced 1 mol of H₂(g).

Thus, the mole ratio is 1 : 1, and 5 moles of Zn are needed to produce 5 moles of H₂(g).

3. Convert 5 moles of Zn to mass in grams

  • mass in grams = number of moles × atomic mass
  • mass = 5 mol × 65.39g/mol = 326.95 g

Round to 3 significant figures: 327g

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