Answer:
KE = 3.308×10^-20J
Explanation:
Let the wavelength of the electron equal the diametre of the protein molecule
Wavelength = 2.70 nm = 2.70 × 10^-7m
The de Brogule expression gives ud:
Wavelength = h/ mv
V = h/m × wavelength
Where h is plank's constant
V = (6.63×10^-11)/(9.11×10^-31)(2.70×10^-9)
V = (6.63×10^-34)/(2.4587×10^-30)
V = 2.695×10^5m/s
KE = 1/2mv^2
KE = 1/2 (9.11×10^-31)( 2.695 ×10^5)^2
KE = 1/2 ×(9.11×10^-31)(7.26×10^10)
KE = 3.308×10^-20J
Answer:
3.32 * 10^-20 J
Explanation:
Let the wavelength of the electron be equal to the diameter if the protein molecule.
λ = 2.7 * 10 ^ -9 m
using De Broglie's equation
λ= h / mv
Where
λ= wavelength
h= Planck's constant
m= mass of the particle
v= velocity of movement of the particle
Then...
v = h / mλ
v = (6.63 * 10^-34) / [(9.11 * 10^-31) * (2.7 * 10^-9)]
v = 2.70 * 10^5 m/s
KE = Kinetic Energy
KE = 1/2mv²
KE = 1/2 (9.11 * 10^-31) * (2.7 * 10^5)²
KE = 3.32 * 10^-20 J
