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The given line segment has a midpoint at (−1, −2).


On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).

HELP ME PLEASE I DONT KNOW THE ANSWER



What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?


y = −4x − 4

y = −4x − 6

y = One-fourthx – 4

y = One-fourthx – 6

Respuesta :

Answer:

The equation of the perpendicular line is y = −4(x) − 6

Step-by-step explanation:

Given:

Three coordinates points (in pair).

Lets choose two points,in [tex](x,y)[/tex] format.

Where

[tex](x,y)[/tex] = [tex](-5,-3)[/tex] and [tex](x_1,y_1)[/tex] = [tex](3,-1)[/tex]

From these points we will find the slope using point-slope formula.

That is :

[tex](y_1-y)=m(x_1-x)[/tex]

[tex]m=\frac{(y_1-y)}{(x_1-x)}[/tex]

Plugging the values:

[tex]m=\frac{-1+3}{3+5}=\frac{1}{4}[/tex]

Now we know that product of slope of two perpendicular lines = -1.

So the slope of the line which is perpendicular [tex](m_1)[/tex] .

[tex]m_1=\frac{-1}{m}[/tex]

[tex]m_1=\frac{-1}{\frac{1}{4} } =-1\times \frac{4}{1} =-4[/tex]

Now using this slope we will plug the midpoint (-1,-2) values in point-slope form and reduced it to slope intercept.

[tex]y-(-2)=-4(x+1)[/tex]

[tex]y+2=-4x-4[/tex]

[tex]y=-4x-4-2[/tex]

[tex]y=-4x-6[/tex]

So the equation of the perpendicular bisector is y = -4(x) - 6

Answer:

y = -4(x) - 6

Step-by-step explanation:

For anyone looking for a simple answer.