Answer:
a) OO/OO (phenotype O) ; OA (ph A)/OB (ph B) ; OO(phO)/ OA(ph A); OO(ph O)/OB (ph B).
b) OB (ph B) or BB (phB) or AB (ph AB).
c) OO(ph O)
Explanation:
a) Blood type 0 is recessive. This girls genotype is OO.
Then, parents need to have at least one allele O each in their genotype. Possibilities genotypes and phenotypes (ph): OO/OO (phenotype O) ; OA (ph A)/OB (ph B) ; OO(phO)/ OA(ph A); OO(ph O)/OB (ph B).
b) Blood type B is co-dominant with A. If the girl is B, it means her genotype can be OB or BB.
But we are told that the mother has blood type A. Also co-dominant. This means the girls genotype cannot be BB.
If the girl is OB, it means she got the O allele from her mother.
The other parent then has to be responsible for the B allele. This means the father could have been OB (ph B) or BB (phB) or AB (ph AB).
c) If the girl is AB (I assume misspelling) and her mother ALSO is AB, then the father cannot be OO(phO). Because he has to give the allele A or B to the girl.
Any other genotype is possible.