Answer:
0 j
Explanation:
Work done from point p1 to point p2 is given by
Work = ∫ F.dr
Here we are given
F= F₀ (x/x₀ -1)
F₀=1.2 N
x₀=3.3 m
dr= dx (since distance changes along x-axis only)
We will calculate above integral between given points x=0 and x= 2x₀
Putting value of F , x₀ and dr
==> Work = ∫ F₀ (x/x₀ -1)
=∫ 1.2 (x/3.3 - 1) dx
= 1.2 /3.3
=∫(x-3.3)dx
=0.363636∫(x-3.3)dx
=0.363636 [ x²/2 - 3.3x]
we are given lower point value x= 0
upper point value x= 2 x₀ = 2× 3.3 = 6.6
putting lower and upper point values of x
= 0.363636 [ {0²/2-3.3(0)} - { (6.6)² /2 - 3.3 × 6.6}]
=0.363636 [ {0}- {43.56 /2 - 21.78}]
=0.363636 [ -{0}]
=0.363636 [0]
=0 j
i-e work is zero joules or no work !
