Answer:
Plane
Step-by-step explanation:
The gunner on a small assault boat fires 6 missiles at an attacking plane. Each has a 20% chance of being on target. If two or more of the shells find their mark, the plane will crash. At the same time, the pilot of the plane fires 10 air-to-surface rockets, each of which has a 0.05 chance of critically disabling the boat. Would you rather be on the plane or on the boat
data for the boat n =6 ; p = 20% = 0.2 ;
at least two or more find their mark the plane will crash
prob.of crash = P(X > =2) = 1-{P(X=0)+P(X =1)}
= 1-{ (0.8)6 + 6*(0.8)5 * 0.2 }
= 1-[0.262144+ 0.3932] = 0.344656
for plane n = 10 ; p = 0.05
for boat crash = P(X > =1 ) = 1- P(X =0) =1-(0.95)10 =0.4013
the prob. for the boat is high
so prefer in the plane