Answer:
center of mass = −0.50 m
Explanation:
given data
mass m1 = 3.04 kg
distance xm = -8 m
mass m2 = 5.61 kg
distance xM = 3.56 m
solution
we get here center of mass for n mass of system that is express as
center of mass = [tex]\frac{m_1x_1+m_2x_2......m_nx_n}{m_1+m_2...m_n}[/tex] ......................1
but we have only 2 particle system so we will get
center of mass = [tex]\frac{m1 \times xm+m2 \times xM}{m1+m2}[/tex] .................2
put here value and we will get
center of mass = [tex]\frac{3.04 \times (-8 )+5.61 \times 3.56}{3.04 + 5.61}[/tex]
solve it we will get
center of mass = −0.50 m
