Respuesta :
Answer: final speed, v2 = 68.79m/s
Explanation:
Given:
Mass, m = 0.140kg
Initial speed, v1= 52.0m/s
Force, F = 8900N
time, t= 1.90ms = 0.0019
Step 1: Using the law of conservation of momentum.
Impulse = summation of momentum
Ft = mv1 + mv2
v2= (Ft-mv1)/m
Step 2: substituting the values
v2 = (8900×0.0019 - 0.14×52)/0.14
v2 = 9.63/0.14
v2 = 68.79m/s
When the bat exerts an average force of 8900 N for 1.90 ms, then the final speed of the ball is 68.79 m/s.
What is the Conservation of momentum?
According to the law of conservation of momentum, the momentum of the system is conserved throughout the process.
As it is given that the Mass, m of the ball is 0.140kg, the initial speed,v1 of the ball is 52.0m/s, and the force, F is 8900 N, also, the time for which thr force is applied on the ball is 1.90ms = 0.0019m.
Now, using the law of conservation of momentum, the impulse force can be written as,
Impulse = summation of momentum
[tex]F_t = mv_1 + mv_2\\\\v_2= \dfrac{(F_t-mv_1)}{m}[/tex]
Substituting the values we get,
[tex]v_2 = \dfrac{(8900\times 0.0019)-(0.14\times 52)}{0.14}\\\\v_2 = \dfrac{9.63}{0.14}\\\\v_2 = 68.79\rm\ m/s[/tex]
Hence, when the bat exerts an average force of 8900 N for 1.90 ms, then the final speed of the ball is 68.79 m/s.
Learn more about Law of conservation of momentum:
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