Answer:
[tex]U_{b}=+7.3*10^{-8}J[/tex]
Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it [tex]W_{a-b}=-1.9*10^{-8}J[/tex]
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:
[tex]W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}[/tex]
Now substitute the given values
So
[tex]U_{b}=5.4*10^{-8}J-(-1.9*10^{-8}J)\\U_{b}=+7.3*10^{-8}J[/tex]
