A store sold 70 hammers and ranchers Hammer sold for $10 each in French so for five dollars each a total of 600.00 what's the collected how many hammers were sold and how many wrenches were sold

Respuesta :

Answer:

50 hammers and 20 wrenches.

Step-by-step explanation:

Let x represent number of hammers and y represent number of ranchers.

We have been given that a store sold 70 hammers and ranchers. We can represent this information in an equation as:

[tex]x+y=70...(1)[/tex]

We are also told that each hammer sold for $10 and each rancher sold for five dollars resulting a total of 600.00. We can represent this information in an equation as:

[tex]10x+5y=600...(2)[/tex]

From equation (1), we will get:

[tex]x=70-y[/tex]

Substituting this value in equation (2), we will get:

[tex]700-10y+5y=600[/tex]

[tex]700-5y=600[/tex]

[tex]700-700-5y=600-700[/tex]

[tex]-5y=-100[/tex]

[tex]\frac{-5y}{-5}=\frac{-100}{-5}[/tex]

[tex]y=20[/tex]

Therefore, 20 wrenches were sold.

Now, we will substitute [tex]y=20[/tex] in equation (1) as:

[tex]x+20=70[/tex]

[tex]x+20-20=70-20[/tex]

[tex]x=50[/tex]

Therefore, 50 hammers were sold.