Respuesta :
Answer:
The answer to the question is
The gravitational force exerted by the Earth on a person when they are on the surface of the Earth compared to when they are orbiting the Earth in a space shuttle 319 km above the surface of the Earth is 1.103 times larger.
Explanation:
From the relation F = G×[tex]\frac{(m)(M)}{r^{2} }[/tex]
Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
m = mass of object one object for which the gravitational force is being measured
M = Mass of Earth
r = Distance between the center of the earth and the object = 12760/2 km = 6380 km
Therefore the gravitational force F for an object placed on the surface of the earth F(earth) = [tex]6.67408(10)^{-11} \frac{(m)(M)}{6371000^{2} }[/tex] = 1.64 × 10⁻²⁴×(m)(M)
and the person is 319 km above the surface of the earth we have
r = 6371 + 319 = 6690 km, therefore the gravitational force becomes
F(orbit) = G × [tex]6.67408(10)^{-11} \frac{(m)(M)}{6690000^{2} }[/tex] = 1.49 × 10⁻²⁴×(m)(M)
Therefore in comparison F(earth)/F(orbit) = 1.103
The gravitational force is 1.103 times larger on the earth than in orbit.
The gravitational force exerted on Earth on the person when they are at surface of Earth compared to when orbiting the Earth in space shuttle the surface of the Earth is 1.103 times larger.
What is the gravitational force ?
The gravitational force is the force that binds the objects together having mass M. The gravitational force is an attractive force as it pulls mas together and includes the newton law of gravitation as force equals to gravitational constant into mas of object 1 upon the mass of object 2 divided by the distance between the center of mass.
The space shuttle having 319 km and a diameter of 12760 km will have a surface that is larger than 1.103 times larger.
Find out more information about the larger/smaller.
brainly.com/question/2142921.
