The adjacent sides of a square are perpendicular lines
The slope of line LK is 4/3
The coordinates of J and K are given as:
J = (-2,5)
K = (2,2)
Start by calculating the slope of JK using:
[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]
So, we have:
[tex]m = \frac{2 -5}{2 + 2}[/tex]
[tex]m = -\frac{3}{4}[/tex]
Lines LK and JK are perpendicular lines.
So, the slope of LK is:
[tex]m_{LK} = -\frac 1m[/tex]
This gives
[tex]m_{LK} = -\frac 1{-3/4}[/tex]
[tex]m_{LK} = \frac 4{3}[/tex]
Hence, the slope of line LK is 4/3
Read more about slopes at:
https://brainly.com/question/1884491
