Answer:
The function whose graph is given below is:
A) [tex]y=3\sin (x-2)+1[/tex]
Step-by-step explanation:
From the graph that is provided to us we observe that,
when x=2
then f(x)=1
Hence, we will check which function satisfies this point.
B)
[tex]y=3\cos(x-3)+1[/tex]
At x=2 we have:
[tex]y=3\cos (3-2)+1\\\\i.e.\\\\y=3\cos(1)+1\\\\y>1[/tex]
Hence, option: B is incorrect.
C)
[tex]y=6\sin (x-2)-2[/tex]
when x=2 we have:
[tex]y=6\sin (2-2)-2\\\\i.e.\\\\y=6\sin 0-2\\\\i.e.\\\\y=-2\neq 1[/tex]
Hence, option: C is incorrect.
D)
[tex]y=3\sin (x-2)+2[/tex]
when x=2 we have:
[tex]y=3\sin (2-2)+2\\\\i.e.\\\\y=3\sin 0+2\\\\i.e.\\\\y=2\neq 1[/tex]
Hence, option: D is incorrect.
So, we are left with option: A
A)
[tex]y=3\sin (x-2)+1[/tex]
when x=2
we get: y=1
Similarly all the other points are satisfied.
Also, the graph of this function matches the given graph.
