Answer:
Explanation:
Given that the road is banked at an angle of 24.0°
a = 3.57g
but a = v^2/r = centripetal acceleration
v = square root (ar)
radius = 229m
v = square root ( 229 x 3.57g)
= square root (229 x 3.57 x 9.81)
= 89.55m/s x 1km/1000m x 3600s/1hr
= 322.29km/hr
b) component of centripetal acceleration = asinФ
= 3.57g x sin 24.0° = 14.24m/s^2
= 1.45g