Explanation:
The given data is as follows.
Voltage (V) = 120 V
Current (I) = 1.39 A
Now, we will calculate the initial resistance using ohm's law as follows.
R = [tex]\frac{V}{I}[/tex]
= [tex]\frac{120}{1.39}[/tex]
= 86.33 ohm
Now, final resistance will be calculated as follows.
R = [tex]\frac{V}{I}[/tex]
= [tex]\frac{120}{1.25}[/tex]
= 96 ohm
Now,
[tex]\Delta R = R \times \alpha \times \Delta T[/tex]
[tex]96 ohm - 86.33 ohm = 88.9 \times 4.5 \times 10^{-4}^{o}C^{-1} \times (T - 20)^{o}C[/tex]
T = [tex]20.02^{o}C[/tex]
Thus, we can conclude that final temperature of the element is [tex]20.02^{o}C[/tex].
