Answer:
y= 4x -5 x^-1
Step-by-step explanation:
xy'+y=8x
y' + y/x =8
linear DE
integrating factor = e^∫1/x dx = x
y = 1/x ( ∫8x dx +C)
y= 1/x (4x^2 +C)
y= 4x + C x^-1
C is any constant.. in this case -5 is satisfying equation
