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A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 9.0 × 10−9 m from the gold nucleus. Collapse question part Part 1 Incorrect answer. Your answer is incorrect. Try again. (a) What is the magnitude of the electric force exerted by the gold nucleus on the electron? Entry field with incorrect answer 5.0667E-10 N the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.

Respuesta :

Answer:

a) 22.471 x 10^-11 N

b) -22.471 x 10^-11 N

Explanation:

given the charge on an electron = 1.6 x 10^-19 C

nucleus contain 79 protons

hence, charge on nucleus =79 x 1.6 x 10^-19 C

distance r = 9 x 10^-9 m

a) therefore, force exerted by the gold nucleus on the electron = Kqe/r^2

= 9 x 10^9 x 79 x 1.6 x 10^-19 x 1.6 x 10^-19 / ( 9 x 10^-9 m)^2

= 22.471 x 10^-11 N

b) force exerted by the electron on the gold nucleus ; = -Force exerted by gold on electron ( From newton third law of motion)

= - 22.471 x 10^-11 N

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