Answer:
629.74 J
Explanation:
Energy: This can be defined as the ability or the capacity to do work.
The S.I unit of energy is Joules (J).
The formula for the energy stored in a capacitor is given as
E = 1/2CV² .............................. Equation 1
Where E = Energy stored in the capacitor, C = capacitance of the heart defibrillator capacitor, V = voltage of the heart defibrillator .
Given: C = 23 µF = 23×10⁻⁶ F, V = 7.4×10³ V.
Substitute into equation 1
E = 1/2(23×10⁻⁶)(7.4×10³)²
E = 629.74 Joules
Hence the energy stored in the the capacitor of a heart defibrillator = 629.74 J
Answer:
629.7 J = 0.63 kJ.
Explanation:
Charge and voltage are related to the capacitance C of a capacitor by Q = CV, and so the expression for Ecap can be written mathematically into three equivalent expressions:
Ecap = QV^2
= 1/2 * (C*V^2)
= 1/2 * Q^2/C
where,
Q = charge
V = voltage on a capacitor C.
The energy is in joules for a charge in coulombs, voltage in volts, and capacitance in farads.
Given:
C = 23.0 µF
= 2.3 x 10^-5 F
V = 7.40 ✕ 10^3 V
Ecap = 1/2 * (C*V^2)
= 1/2 * (2.3 x 10^-5) * (7.40 ✕ 10^3)^2
= 629.7 J
= 0.63 kJ.
