Respuesta :
Answer:
Δt = 8 x 10^6secs , Δt in days = 92.6days
1 day = 86400secs
Explanation:
- The concept of momentum is applied here.
- momentum is the product of mass and change in velocity
- mathematically p = mΔv
- p = momentum, m = mass of the body, Δv = change in velocity
- acceleration a = Δv/Δt
- Δv = aΔt
the impulse is the product of the force and the change in time;
mathematically I = FΔt
- as such Impulse = change in momentum
- I = Δp
- mΔv = I = FΔt
- Δt = mΔv/F
- but m = 1.0 x 10^10 kg, Δv = 0.20cm/s or 0.002m/s, F = 2.5N
- Plugging the values into ; Δt = mΔv/F = 1.0 x 10^10 kg x 0.002m/s x 2.5N
- Δt = 8 x 10^6secs , Δt in days = 92.6days
- N/B ; 1 day = 86400secs
The force will act at Δt = [tex]8 * 10^6secs[/tex] , Δt in days = 92.6 days
Impulse:
It is the product of the resultant force F and the duration of this force Δt, if the force is constant. Impulse of force is the cause of changes to motion and therefore changes to momentum.
Momentum is given as:
p = mΔv
p = momentum, m = mass of the body, Δv = change in velocity
acceleration a = Δv/Δt
Δv = aΔt
Given:
- m = [tex]1.0 * 10^{10} kg[/tex],
- Δv = 0.20cm/s or 0.002m/s,
- F = 2.5N
Substituting the values in the equation given below.
[tex]I = \triangle p\\\\m \triangle v = I = F \triangle t\\\\ \triangle t =\frac{m \triangle v}{F}\\\\\\ \triangle t = 1.0 *10^{10} kg * 0.002m/s * 2.5N\\\\ \triangle t = 8 * 10^6secs , \triangle t \text{ in days} = 92.6days[/tex]
Find more information about Impulse here:
brainly.com/question/904448
