Respuesta :

tanmayakumarp3

Answer:

8 feet

Step-by-step explanation:

Given,

Perimeter of a rectangular pool (P) = 40 feet

Length of the pool (l) = 12 feet

Let,

Width of the pool be = w

As we know,

  • Perimeter of a rectangle = 2(length + width)

Therefore,

By the problem,

=> 2(l + w) = P

  • [On substituting the values of l = 12 and P = 40]

=> 2(12 + w) = 40

  • [On multiplying 2 with 12 and w]

=> 24 + 2w = 40

  • [On subtracting both sides with 24]

=> 24 - 24 + 2w = 40 - 24

  • [On Simplifying]

=> 2w = 16

  • [On Dividing both sides with 2]

=> [tex]\frac{2w}{2}[/tex] = [tex]\frac{16}{2}[/tex]

  • [On Simplifying]

=> w = 8

Hence,

The required width of the pool is 8 feet. (Ans)

MisterBrian

Answer:

The Width of the pool would be 8 feet/ft. .

Step-by-step explanation:

According to the Question Given:

Perimeter = 40 ft/feet

Length of the pool = 12 ft/feet

To Find:

The width/breadth of the pool

Solution:

We know that,

[tex] \boxed{\tt \: Perimeter \: of \: Rectangle = 2(l + b)}[/tex]

So Put their values accordingly:

  • Perimeter of The Rectangle = 40
  • Length[L] = 12

[tex]\longrightarrow \tt \: 40 = 2(12 + b)[/tex]

We got an equation.By this method we can easily find the breadth/width of the pool.

Solve this equation:

[tex]\longrightarrow \tt40 = 2b + 24[/tex]

Flip the equation:

[tex]\longrightarrow \tt2b + 24 = 40[/tex]

  • Transpose 24 to the RHS[remember to change its sign]:

[tex]\longrightarrow \tt2b = 40 - 24[/tex]

  • Simplify:

[tex]\longrightarrow \tt2b = 16[/tex]

Divide both sides by 2:

[tex] \tt\longrightarrow \cfrac{2b}{2} = \cfrac{16}{2} [/tex]

  • Use Cancellation method and cancel LHS and RHS:

[tex]\tt\longrightarrow \cfrac{ \cancel2 {}^{1} b}{ \cancel2} = \cfrac{ \cancel{16} {}^{8} }{ \cancel2} [/tex]

[tex]\longrightarrow \tt1b = 8[/tex]

[tex]\longrightarrow \tt{b} =\boxed{\tt 8 \: feet}[/tex]

Hence, the breadth/width of the pool would be 8 ft./feet .

[tex] \rule{225pt}{2pt}[/tex]

I hope this helps!

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