Answer:
9.17%
Step-by-step explanation:
The probability of a positive indication by a mammogram is given by the probability of positive indication when a woman has cancer, added to the probability of positive indication when a woman does not have cancer.
[tex]P(+) = P(C)*P(+_C)+(1-P(C))*P(+_n)\\P(+) = 0.01*0.9+(1-0.01)*0.09\\P(+) = 0.0981[/tex]
Given that the indication is positive, the probability that a woman actually has cancer is:
[tex]P(C|+) = \frac{P(C)*P(+_C)}{P(+)}\\ P(C|+) =\frac{0.01*0.9}{0.0981}\\P(C|+)= 0.0917 = 9.17\%[/tex]
The probability that the randomly selected woman has cancer is 9.17%