Answer:
b. 2
Step-by-step explanation:
The Central Limit Theorem is important to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\frac{\sigma}{\sqrt{n}}[/tex]. This standard deviation, of the sample, is also called standard error of the mean.
In this problem, we have that:
[tex]\sigma = 14, n = 49[/tex]
The standard error of the mean is
[tex]\frac{14}{\sqrt{49}} = 2[/tex]
So the correct answer is:
b. 2
The standard error of the mean is 2.
given,
Number of sample is 49.
The standard deviation of sample is 14.
We know that, the standard error of the mean is calculated by dividing the standard deviation by the square root of sample selected.
[tex]\rm SE=\dfrac{\sigma}{\sqrt{n} }[/tex]
Here [tex]\sigma[/tex] is the standard deviation and n is the number of sample.
So,
[tex]\rm SE=\dfrac{14}{\sqrt{49} }[/tex]
[tex]\rm SE=\dfrac{14}{7}[/tex]
[tex]\rm SE =2[/tex].
Hence the correct option will be (b). 2
For more details on Standard error of the mean follow the link:
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