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At a certain temperature K = 1.1 X 10^3 L/mol for the reaction given below. Calculate the concentrations of Fe3+, SCN?, and FeSCN2+ at equilibrium if 0.020 mol of Fe(NO3)3 is added to 1.0 L of 0.10 M KSCN. (Neglect any volume change.)Fe3+(aq) + SCN ?(aq) FeSCN2+(aq)Fe3+____________MSCN- ______________MFeSCN2+ ____________M

Respuesta :

Answer:

Explanation:

Fe⁺³ + SCN⁻ =  FeSCN²⁺

x           x                x

If x mole of Fe⁺³ reacted , unreacted Fe⁺³ = .02 - x

Remaining SCN⁻  unreacted = .1 - x

K_c =   [ FeSCN²⁺] / [Fe⁺³] [ SCN⁻]

1.1 x 10³ =  x  / ( .02 - x ) (.1 - x )

1100 = x / .002 - .12x ( neglecting x² )

x = .0165

Concentration of Fe⁺³ = .02 - x = .0035 M

Concentration of SCN⁻ = .1 - x = .0835 M

Concentration of FeSCN²⁺ = x = .0165M