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A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 kg/m3.

What mass must be placed on the small piston to support a car of mass 1100 kg at equal fluid levels?

Respuesta :

Answer:

Explanation:

Given

Cross-sectional area of two areas is

[tex]A_1=15\ cm^2[/tex]

[tex]A_2=670\ cm^2[/tex]

It is filled with oil of density [tex]\rho _0=510\ kg/m^3[/tex]

mass of car place on Large area [tex]M=1100\ kg[/tex]

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

[tex]P_1=P_2[/tex]

[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]

[tex]\frac{mg}{15}=\frac{Mg}{670}[/tex]

[tex]m=1100\times \frac{15}{670}[/tex]

[tex]m=24.62\ kg[/tex]                            

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