Answer:
minimum deceleration = 12.5 ft/s²
Explanation:
Data provided in the question:
Initial speed of the car, u = 50 ft/s
Distance to cover, s = 100 ft
Final speed of the car = 0 ft/s [ ∵ as the car stops ]
Now,
from the Newton's equation of motion
we have
v² - u² = 2as
a is the acceleration
on substituting the respective values, we get
0² - 50² = 2 × a × 100
or
- 2500 = 200a
or
a = - 12.5 ft/s²
Here, the negative sign depicts the deceleration.
