Respuesta :
[tex]\bf (\stackrel{x_1}{15}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{15}}}\implies \cfrac{0}{-17}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{0}(x-\stackrel{x_1}{15})\implies y-9=0\implies y=9[/tex]