Answer: Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to a greater extent than adding 1 mol of [tex]C_6H_12O_6[/tex] to 1 kg of water.
Explanation:
It is known that lowering of vapor pressure is a colligative property that basically depends on the number of solute particles dissolved in the solvent, i.e, water.
Hence, higher is the number of particles present in a solution more will be the lowering in vapor pressure.
For example, NaCl is an ionic compound and a strong electrolyte. So, it will dissociate as follows.
[tex]NaCl \rightarrow Na^{+} + Cl^{-}[/tex]
On the other hand, [tex]C_{6}H_{12}O_{6}[/tex] is actually a molecular compound and it acts as a non-electrolyte. Therefore, it does not dissociate into ions.
Therefore, we can conclude that as NaCl is able to generate more number of solute particles hence, it will lead to the lowering of vapor pressure to a greater extent.
