Respuesta :
Answer:
α = 1.32 rad/s²
Explanation:
given,
diameter of the bicycle = 0.8 m
radius of the bicycle = 0.4 m
initial speed of the bicyclist,u = 0 m/s
final speed of the bicyclist,v = 22 Km/h = 22 x 0.278
= 6.12 m/s
time,t = 11.6 s
acceleration =[tex]\dfrac{v-u}{t}[/tex]
=[tex]\dfrac{6.12-0}{11.6}[/tex]
=0.53 m/s²
we know,
a = α r
[tex]\alpha=\dfrac{a}{r}[/tex]
[tex]\alpha=\dfrac{0.53}{0.4}[/tex]
α = 1.32 rad/s²
the angular acceleration of the wheels is equal to α = 1.32 rad/s²
