The liquid pressure is equal to the product of the weight density and the depth. The pressure of the liquid depends on the depth and the density of the liquid. The mathematical expression is
[tex]P = \dot{\rho} h[/tex]
Where,
[tex]\dot{\rho} =[/tex] Weight density
h = Depth
Replacing we have that
[tex]P = (9800N/m^3)(1.2m)[/tex]
[tex]P = 11800Pa[/tex]
[tex]P = 11.8kPa[/tex]
Therefore the water pressure on the bottom of the barrel is 11.8kPa