Answer:
Empirical formula is C₇H₅F₃
Explanation:
Given data:
Percentage of hydrogen = 3.45%
Percentage of carbon = 57.54%
Percentage of fluorine = 39.01%
Empirical formula = ?
Solution:
Number of gram atoms of H = 3.45 / 1.01 = 3.42
Number of gram atoms of F = 39.01 / 18.99 = 2.05
Number of gram atoms of C = 57.54/ 12.01 = 4.79
Atomic ratio:
C : H : F
4.79/2.05 : 3.42/2.05 : 2.05/2.05
2.34 : 1.67 : 1
C : H : F = 3(2.34 : 1.67 : 1 )
Empirical formula is C₇H₅F₃.
