At "-48 F
" the air temperatures be closest to 1,000 feet/sec. A further explanation is below.
According to the question or we know that,
or,
- [tex]a = 1052+1.08t[/tex]
By substituting the given value, we get
→ [tex]1000= 1052+1.08t[/tex]
By subtracting "1052" from both sides of equation, we get
→ [tex]1000-1052= 1052+1.08t-1052[/tex]
→ [tex]-52 = 1.08t[/tex]
→ [tex]t = -\frac{52}{1.08}[/tex]
→ [tex]= -48.15[/tex]
or,
→ [tex]= -48^{\circ} F[/tex]
Thus the above answer i.e., option B) is the appropriate one.
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