Answer:
[tex]Ag^+, Pb^{2+}, Hg_2^{2+}[/tex]
Explanation:
The majority of metal chloride salts are soluble, however, there are notable exceptions. When chloride ions are added to a solution containing lead(II) cations, silver cations or mercurous cations, precipitates are formed.
When silver cations react with chloride, we obtain an insoluble silver chloride:
[tex]Ag^+ + Cl^-\rightarrow AgCl[/tex]
When lead(II) cations react with chloride anions, lead(II) precipitate is formed, however, it becomes soluble at higher temperatures:
[tex]Pb^{2+} + 2 Cl^-\rightarrow PbCl_2[/tex]
Finally, the final precipitate would be:
[tex]Hg_2^{2+} + 2 Cl^-\rightarrow Hg_2Cl_2[/tex].
