Answer:
5 mm
Explanation:
Youngs's modulus (Y) is described by the following expression:
[tex]Y=\frac{F*L}{\Delta L*A}[/tex]
Where F is the force exerted on the tendon, L is its length, A is its area and ΔL is its change in length (stretching).
The force in this case is 8 times the weight of the runner:
[tex]F= 8*m*g\\F= 8*70*9.8\\F=5488 N[/tex]
Therefore, the change in length of the tendon is given by:
[tex]\Delta L=\frac{F*L}{Y*A}\\\Delta L=\frac{5488*0.15}{0.15*10^{10}*1.1*10^{-4}}\\\Delta L= 0.004989 m[/tex]
the runner's Achilles tendon will stretch by 0.004989 m, which is roughly 5 mm.