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Some cells, such as intestinal cells, exchange a lot of material with their surroundings. The surface-to-volume ratio of these cells affects the efficiency of material exchange.
The table provides measurements of four different eukaryotic cells.
Cell 1 2 3 4
Total surface area (μm2) 40 60 80 100
Total volume (μm3) 20 10 30 20
Based on the data, which cell is likely to be most effective in the exchange of materials?

A.Cell 1
B.Cell 2
C.Cell 3
D.Cell 4

Respuesta :

Answer:

Option B, Cell 2

Explanation:

The rate at which cell shall exchange material depends upon the ration of surface area to volume.

We shall calculate the surface area/volume ratio of each cell -

For cell 1

Surface area [tex]= 40[/tex]

Volume [tex]= 20[/tex]

Surface area -volume ration

[tex]\frac{40}{20} \\= 2[/tex]

For cell 2

Surface area [tex]= 60[/tex]

Volume [tex]= 10[/tex]

Surface area -volume ration

[tex]\frac{60}{10} \\= 6[/tex]

For cell 3

Surface area [tex]= 80[/tex]

Volume [tex]= 30[/tex]

Surface area -volume ration

[tex]\frac{80}{30} \\= 2.67[/tex]

For cell 4

Surface area [tex]= 100[/tex]

Volume [tex]= 20[/tex]

Surface area -volume ration

[tex]\frac{100}{20} \\= 5[/tex]

Hence, the correct answer is option B, i.e cell 2

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