Respuesta :
Answer:
2.94x10²² atoms of Cu
Explanation:
We must work with NA to solve this, where NA is the number of Avogadro, number of particles of 1 mol of anything.
Molar mass Cu = 63.55 g/mol
Mass / Molar mass = Mol → 3.11 g / 63.55 g/m = 0.0489 moles
1 mol of Cu has 6.02x10²³ atoms of Cu
0.0489 moles of Cu, will have (0.0489 .NA)/ 1 = 2.94x10²² atoms of Cu
There are 2.94 x 10²²atoms in 3.11 grams of copper penny.
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We first find the number of moles contained in 3.11 grams of copper
Number of moles =Mass/ Molar mass
Molar mass of copper is 63.546g/mol
Number of moles = 3.11 g/63.546g/mol =0.0489moles
But 1 mole of Cu= 6.022x10²³(Avogadro's number ) atoms of Cu
Therefore 0.0489 moles of Cu will give 0.0489 x 6.02x10²³ atoms Cu =2.94 x 10²²atoms