Answer:
Explanation:
Initial velocity (u) of the Bullet = 400 m/sec
Final velocity (v) of the Bullet = 100 m/sec
Bullet passed through the block in (t) = 0.0004 sec
Using 1st Equation of motion :
400 m/s = 100 m/s - a (0.0004)
Deceleration of Bullet = 750,000 m/sec^2
(a) F (force exerted by the wooden block on the bullet) = F (force exerted by the bullet on the wooden block)
F = m * a = 0.008 * 750,000 = 6000 N
(b) Using 3rd Equation of motion :
[tex]v^{2} = u^{2} - 2aS[/tex]
10000 = 160000 - 2 * 750,000 * S
Thickness of wood (S) = 0.1 m
