The equation of the second street is y= -x+6.
Step-by-step explanation:
The graph for the question uploaded below.
The street 1's slope will be the same for street 2 since they are parallel.
To find the slope of the street 1, choose two points from the passing line.
The formula for finding slope,[tex]m=\frac{rise}{run}[/tex].
[tex]rise =y_{2}-y_{1}[/tex] and [tex]run =x_{2}-x_{1}[/tex].
Here let us take (0,1) and (1,0).
rise=0-(1). and run =1-0.
rise= -1 and run 1.
[tex]m=\frac{-1}{1}[/tex].
m= -1.
The line equation is given by y=mx+c.
substitute m value in this equation.
∴y= -x+c.
we know that the point that street 2 pass through is (1,5).
Substitute this point to find the y-intercept c.
5= -1+c.
c=1+5.
c=6.
∴ The equation for the second street is y= -x+6.
